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x^2+19x-2200=0
a = 1; b = 19; c = -2200;
Δ = b2-4ac
Δ = 192-4·1·(-2200)
Δ = 9161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-\sqrt{9161}}{2*1}=\frac{-19-\sqrt{9161}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+\sqrt{9161}}{2*1}=\frac{-19+\sqrt{9161}}{2} $
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